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Question

Physics Question on Moment Of Inertia

Two identical concentric rings each of mass mm and radius RR are placed perpendicularly. What is the moment of inertia about axis of one of the rings

A

32MR2\frac{3}{2}MR^2

B

2MR22MR^2

C

3MR23MR^2

D

14MR2\frac{1}{4}MR^2

Answer

32MR2\frac{3}{2}MR^2

Explanation

Solution

Since the axis of two rings are also perpendicular to each other, therefore applying the theorem of perpendicular axes
I=MR2+12MR2I=M R^{2}+\frac{1}{2} M R^{2}
32MR2\frac{3}{2} M R^{2}