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Physics Question on Magnetic Field

Two identical circular wires of radius 20 cm and carrying current 2\sqrt2 A are placed in perpendicular planes as shown in figure. The net magnetic field at the centre of the circular wires is _________ × 10^{-8} T.

Two identical circular wires of radius 20 cm

Answer

Bnet=μ0i2ri^+μ0i2rȷ^ Bnet =μ0i2r2=4π×107×2×2×12×0.2=2×3.14×106=628×108 T\begin{aligned} & \overrightarrow{B_{n e t}}=\frac{\mu_0 i}{2 r} \hat{i}+\frac{\mu_0 i}{2 r} \hat{\jmath} \\\ & \Rightarrow B_{\text {net }}=\frac{\mu_0 i}{2 r} \sqrt{2}=4 \pi \times 10^{-7} \times \sqrt{2} \times \sqrt{2} \times \frac{1}{2 \times 0.2}=2 \times 3.14 \times 10^{-6}=628 \times 10^{-8} \mathrm{~T} \end{aligned}