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Question: Two identical charges are placed at the two corners of an equilateral triangle. The potential energy...

Two identical charges are placed at the two corners of an equilateral triangle. The potential energy of the system is U. The work done in bringing an identical charge from infinity to the third vertex is-

A

U

B

2U

C

3U

D

4U

Answer

2U

Explanation

Solution

Ui = kq2a\frac { \mathrm { kq } ^ { 2 } } { \mathrm { a } } = U

Uf = 3kq2a\frac { 3 \mathrm { kq } ^ { 2 } } { \mathrm { a } } = 3U

W = Uf – Ui = 3U – U = 2U