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Question

Physics Question on coulombs law

Two identical charged spheres are suspended by strings of equal lengths. The strings make an angle of 3030^{\circ} with each other. When suspended in a liquid of density 0.8gcm30.8\, g\, cm^{-3}, the angle remains the same. If density of the material of the sphere is 16gcm316\, g\, cm^{-3}, the dielectric constant of the liquid is

A

4

B

3

C

2

D

1

Answer

2

Explanation

Solution

From F.B.D of sphere, using Lami?? theorem Fmg=tanθ(i)\frac{F}{mg} = tan\theta \quad\quad\dots\dots\dots\dots\dots\dots\left(i\right) when suspended in liquid, as q remains same, Fmg(1ρd)=tanθ(ii)\therefore\quad \frac{F'}{mg\left(1-\frac{\rho}{d}\right)} = tan\,\theta \quad\dots\dots\dots\dots\dots\dots\left(ii\right) using (i)\left(i\right) and (ii)\left(ii\right) Fmg=Fmg(1ρd)\frac{F}{mg} = \frac{F'}{mg\left(1-\frac{\rho }{d}\right)} where, F=FKF' = \frac{F}{K} Fmg=Fmg(1ρd)\therefore\quad \frac{F}{mg} = \frac{F'}{mg\left(1-\frac{\rho }{d}\right)} or K=11ρd=2\quad K = \frac{1}{1-\frac{\rho}{d}} = 2