Solveeit Logo

Question

Question: Two identical charged particles enter a uniform magnetic field with the same speed but at angles \({...

Two identical charged particles enter a uniform magnetic field with the same speed but at angles 300{30^0} and 600{60^0} with the field. Let a, b, and c be the ratio of their time periods, radii, and pitches of the helical paths then:
A. abc=1abc = 1
B. abc>1abc > 1
C. abc<1abc < 1
D. a=bca = bc

Explanation

Solution

As we know that a moving charge produces a magnetic field. Similarly, a moving charge experiences a thrust in a magnetic field which depends on the speed and angle at which the particle enters the magnetic field. Depending on this angle the particle takes different paths.

Complete step by step solution:
Let us first write the information given in the question.
The charged particles enter the uniform magnetic field with different angles and the same velocities.
θ1=30,θ2=60{\theta _1} = 30,{\theta _2} = 60 , and a, b, and c are the ratio of their time-period, radii, and pitches.
We have the following formula to calculate the time period of a charged particle in a magnetic field.
T=2πmqBT = \dfrac{{2\pi m}}{{qB}}
Here, mm is the mass of the particle, qq is the charge of the particle, and BB is the magnetic field.
So, the ratio of the time periods of these two particles is given below.
T1T2=1=a\dfrac{{{T_1}}}{{{T_2}}} = 1 = a (1)

Now the formula to calculate the radius is given below.
R=mvsinθqBR = \dfrac{{mv\sin \theta }}{{qB}}
Here, mm is the mass, vv is the speed, qq is a charge, BB is the magnetic field, and θ\theta is the angle with which it enters the magnetic field.
Now, let us find the ratio of their radii.
R1R2=sin30sin60=13=b\dfrac{{{R_1}}}{{{R_2}}} = \dfrac{{\sin 30}}{{\sin 60}} = \dfrac{1}{{\sqrt 3 }} = b (2)
The formula to calculate the pitch of the path is given by the following formula.
l=tvcosθl = tv\cos \theta
Here, ttis the time, vv is the velocity and θ\theta is the angle with which the particle entered.
Now, let us find the ratio of their pitches.
l1l2=cos30cos60=3=c\dfrac{{{l_1}}}{{{l_2}}} = \dfrac{{\cos 30}}{{\cos 60}} = \sqrt 3 = c (3)
Now let us multiply equations (1), (2), and (3).
abc=1abc = 1
Hence, the correct option is (A) abc=1abc = 1.

Note:
When a particle enters at an angle less than a right angle, its path is helical. Similarly, when a particle enters perpendicular to the magnetic field its path is circular.
When a particle enters in the direction of a magnetic field it experiences no force. Similarly, when it enters just opposite the direction of a magnetic field, the force experienced is maximum but in both cases, the path will be a straight line.