Question

Two identical charged particles each having a mass 10 g and charge $2.0 × 10^{–7}$ C are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is $0.25$, find the value of L. [Use g = $10$ $ms^{–2}$]

• A. 12 cm
• B. 10 cm
• C. 8 cm
• D. 5 cm

Answer 1

Answer: (A)

12 cm

Answer 2

According to given information:

$\frac{KQ^2}{L^2} = μmg$

Putting the values, we get

$L = 12$ $cm$