Question
Question: Two identical capacitors A and B shown in the given circuit are joined series with a battery. If a d...
Two identical capacitors A and B shown in the given circuit are joined series with a battery. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B and battery remains connected, then the energy of capacitor A will-
A
Increase
B
Decrease
C
Remain the same
D
Be zero since circuit will not work
Answer
Increase
Explanation
Solution
Initial charge on capacitor A, Q = 
After dielectric is inserted
After inserting dielectric, charge on capacitor A
As K > 1 \ Q¢ > Q
\U¢ > U 