Solveeit Logo

Question

Physics Question on Electric Power

Two identical batteries each of e.m.f 2 V and internal resistance 1Ω1\, \Omega are available to produce heat in an external resitance by passing a current through it. The maximum power that can be developed across R using these batteries is

A

3.2 W

B

2.0 W

C

1.28 W

D

89W\frac{8}{9} W

Answer

2.0 W

Explanation

Solution

For maximum current, the two batteries should be connected in series. The current will be maximum when external resistance is equal to the total internal resistance of cells i.e.2Ω2\, \Omega.
Hence power developed across the resistance R will be

I2R=(2ER+2r)2R=(2×22+2)2×2=2W\, \, \, \, \, I^2R=\bigg(\frac{2E}{R+2r}\bigg)^2 \, \, R=\bigg(\frac{2 \times 2}{2+2}\bigg)^2 \times 2 = 2\, W