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Question: Two identical balls A and B of mass m kg are attached to two identical massless springs. The spring ...

Two identical balls A and B of mass m kg are attached to two identical massless springs. The spring mass system is constrained to move inside a rigid pipe bent in the form of a circle as shown in figure. The pipe is fixed in a horizontal plane. The centres of the balls can move in a circle of radius r metre. Each spring has a natural length of rπmetre and spring constant K. Initially, both the balls are displaced by an angle 8 radian with respect to diameter PQ of the circles and released from rest. The speed of ball A when A and B are at the two ends of dia PQ is

A

mK\sqrt{\frac{m}{K}}

B

2RθKm2R\theta\sqrt{\frac{K}{m}}

C

2RθmK2R\theta\sqrt{\frac{m}{K}}

D

RθKmR\theta\sqrt{\frac{K}{m}}

Answer

2RθKm2R\theta\sqrt{\frac{K}{m}}

Explanation

Solution

In stretched position of spring.

system P.E. = 2 × 12\frac{1}{2}k × 2x2 = 4kx2

In mean position, both balls have kinetic energy only;

K.E. = 2[12mv2]=mv2\left\lbrack \frac{1}{2}mv^{2} \right\rbrack = mv^{2}

but P.E. = K.E.

∴ 4Kx2 = mv2

or v = 2xKm\sqrt{\frac{K}{m}} = 2RθKm\sqrt{\frac{K}{m}}