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Physics Question on Elastic and inelastic collisions

Two identical balls A and B collide head on elastically. If the velocity of A and B before collision are 0.5 ms−10.5\, ms^{-1} and 0.3 ms−1ms^{-1} respectively, then their velocities after collision will be

A

0.5 ms−10.5\, ms^{-1} and 0.3 ms−1 0.3\, ms^{-1}

B

−0.5 ms−1-0.5\, ms^{-1} and 0.3 ms−10.3 \,ms^{-1}

C

0.3 ms−10.3\, ms^{-1} and −0.5 ms−1-0.5 \,ms^{-1}

D

−0.3 ms−1-0.3\, ms^{-1} and 0.5 ms−10.5\, ms^{-1}

Answer

−0.3 ms−1-0.3\, ms^{-1} and 0.5 ms−10.5\, ms^{-1}

Explanation

Solution

In elastic collision, the bodies come to their original shape and size after the collision with interchange of their velocity.
Therefore, velocity of A=−0.3ms−1A = -0.3 ms^{-1}
velocity of B =0.5ms−1. 0.5 ms^{-1.}