Question

Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is

• A. 0.75 A
• B. zero
• C. 0.25 A
• D. 0.5 A

Answer 1

Answer: (D)

0.5 A

Answer 2

In the given circuit the upper diode $D_1$ is forward biased and the lower diode $D_2$ is reverse blased. So, the current supplied by the battery is
$I=\frac{5 V}{10\Omega}=\frac{1}{2}A=0.5\, A$