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Question

Physics Question on Resistance

Two ideal batteries of emfV1emf V _{1} and V2V _{2} and three resistances R1,R2R _{1}, R _{2} and R3R _{3} are connected as shown in the figure. The current in resistance R2R _{2} would be zero if

A

V1=V2V _{1}= V _{2} and R1=R2=R3R _{1}= R _{2}= R _{3}

B

V1=V2V _{1}= V _{2} and R1=2R2=R3R _{1}=2 R _{2}= R _{3}

C

V1=2V2V _{1}=2 V _{2} and 2R1=2R2=R32 R _{1}=2 R _{2}= R _{3}

D

2V1=V22 V _{1}= V _{2} and 2R1=R2=R32 R _{1}= R _{2}= R _{3}

Answer

2V1=V22 V _{1}= V _{2} and 2R1=R2=R32 R _{1}= R _{2}= R _{3}

Explanation

Solution

V1=R1(V1+V2)R1+R3V _{1}=\frac{ R _{1}\left( V _{1}+ V _{2}\right)}{ R _{1}+ R _{3}} V1R3=V2R1 \Rightarrow V _{1} R _{3}= V _{2} R _{1} V2=R3(V1+V2)R1+R3V _{2}=\frac{ R _{3}\left( V _{1}+ V _{2}\right)}{ R _{1}+ R _{3}} V2R1=V2R3\Rightarrow V _{2} R _{1}= V _{2} R _{3}