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Question

Physics Question on Electric Power

Two heater wires of equal length are first connected in series and then in parallel. The ratio of heat produced in the two cases is

A

1:02

B

2:01

C

1:04

D

4:01

Answer

1:04

Explanation

Solution

H1=V2t2RH_1 = \frac{V^2t}{2R} ( \because R' = R + R =2R) H2=2V2tRH_2 = \frac{2V^2t}{R} (1R=1R+1R=2R)\left ( \because \frac{1}{R'} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R} \right) \therefore H12=14\frac{H_1}{_2} = \frac{1}{4}