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Question: Two glass bulbs A and B are connected by a very small tube having a stop cock. Bulb A had a volume o...

Two glass bulbs A and B are connected by a very small tube having a stop cock. Bulb A had a volume of 100cm3100c{m^3} and contained the gas, while bulb B was empty. On opening the stop cock, the pressure fell down 40%40\%. The volume of the bulb must be?
A. 75cm375c{m^3}
B. 125cm3125c{m^3}
C. 150cm3150c{m^3}
D. 250cm3250c{m^3}

Explanation

Solution

The product of pressure of A and volume of A is equal to the product of final volume and pressure of the whole system. This is in accordance with Boyle's law. The final volume is the sum of volume of A and B. As the pressure decreases to 40%, so the final pressure will be 40% of initial pressure.

Complete Step by step answer:
Two glass bulbs named as A and B are connected by a small tube with a stop cock attached to it. Bulb A is filled with the gas and has a volume of 100cm3100c{m^3} and bulb B is empty. The purpose of the stop cock is to prevent the movement of gas from bulb A to bulb B.

Now, the stop cock is opened and the pressure falls down to 40%40\% of initial pressure. Let the initial volume be represented by Vi=100cm3{V_i} = 100c{m^3}, initial pressure be Pi{P_i}, final volume be Vf=100+V2{V_f} = 100 + {V_2} (since the stop cock is opened, so the final volume will be the sum of total volume of bulb A and B) and final pressure be Pf=40%{P_f} = 40\% of Pi{P_i} i.e., 40Pi100\dfrac{{40{P_i}}}{{100}}. V2{V_2} denotes the volume of glass bulb B.

According to Boyle’s law, the product of pressure (P)\left( P \right) and volume (V)\left( V \right) is constant (k)\left( k \right) at constant temperature i.e., PV=kPV = k. So, we can write PiVi=k{P_i}{V_i} = k and PfVf=k{P_f}{V_f} = k. Thus, PiVi=PfVf{P_i}{V_i} = {P_f}{V_f}
Pi×100=(40Pi100)×(100+V2)\Rightarrow {P_i} \times 100 = \left( {\dfrac{{40{P_i}}}{{100}}} \right) \times \left( {100 + \Rightarrow {V_2}} \right)
100Pi=(2Pi5)×(100+V2)\Rightarrow 100{P_i} = \left( {\dfrac{{2{P_i}}}{5}} \right) \times \left( {100 + {V_2}} \right)
100×52=100+V2\Rightarrow 100 \times \dfrac{5}{2} = 100 + {V_2}
250=100+V2\Rightarrow 250 = 100 + {V_2}
V2=250100\Rightarrow {V_2} = 250 - 100
V2=150cm3\Rightarrow {V_2} = 150c{m^3}

Therefore, option C is correct.

Note: Remember that the initial volume will be the volume of glass bulb A only as glass bulb B was initially empty and final volume will be the sum of volume of A and B as the gas flows from bulb A to bulb B after opening the stop cock and also memorize the Boyle’s law as it gives us the main idea to solve this problem.