Question

Two glass bulbs $A$ and $B$ are connected by a very small tube having a stop-cock. Bulb $A$ has a volume of $100\, cm^3$ and contained the gas while bulb $B$ was empty. On opening stop-clock, the pressure fell down to $40\%$. The volume of the bulb $B$ must be

• A. $75\, cm^3$
• B. $125\, cm^3$
• C. $150\, cm^3$
• D. $250\, cm^3$

Answer 1

Answer: (C)

$150\, cm^3$

Answer 2

$\therefore 100 � p = V_{2} � \frac{40P}{100}$
$V_{2} = 250\, cc$ (Total volume)
Volume of bulb $B = 250 - 100 = 150\, cc$