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Question: Two friends A and B have equal number of daughters. There are three cinema tickets which are to be d...

Two friends A and B have equal number of daughters. There are three cinema tickets which are to be distributed among the daughters of A and B. The probability that all the tickets go to daughters of A is 1/20. The number of daughters each of them have is

A

4

B

5

C

6

D

3

Answer

3

Explanation

Solution

Let each of the friend have x daughters. Then the probability that all the tickets go to the daughters of A is xC32xC3\frac { { } ^ { \mathrm { x } } \mathrm { C } _ { 3 } } { { } ^ { 2 \mathrm { x } } \mathrm { C } _ { 3 } } . Therefore xC32xC3=120x=3\frac { { } ^ { \mathrm { x } } \mathrm { C } _ { 3 } } { { } ^ { 2 \mathrm { x } } \mathrm { C } _ { 3 } } = \frac { 1 } { 20 } \Rightarrow \mathrm { x } = 3