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Question

Physics Question on Forces

Two forces F1F_1 and F2F_2 are applied on two rods PP and QQ of same materials such that elongation in rods are same. If ratio of their radii is x:yx : y and ratio of length is m:nm : n, then ratio of F1:F2F_1 : F_2 is

A

(yx)2nm\bigg(\frac{y}{x}\bigg)^2\frac{ n}{m}

B

(xy)2nm\bigg(\frac{x}{y}\bigg)^2 \frac{n}{m}

C

(yx)2mn\bigg(\frac{y}{x}\bigg)^2 \frac{m}{n}

D

(yx)2mn\bigg(\frac{y}{x}\bigg)^2 \frac{m}{n}

Answer

(xy)2nm\bigg(\frac{x}{y}\bigg)^2 \frac{n}{m}

Explanation

Solution

The correct option is (B): (xy)2nm\bigg(\frac{x}{y}\bigg)^2 \frac{n}{m}