Solveeit Logo

Question

Question: Two finite sets \(A\) and \(B\) have \(m\) and \(n\) elements respectively. If the total number of s...

Two finite sets AA and BB have mm and nn elements respectively. If the total number of subsets of AA is 112112 more than the total number of subsets of BB, then the value of m is:
A. 77
B. 99
C. 1010
D. 1212
E. 1313

Explanation

Solution

In the given question, we are provided with two finite sets AA and BB. The number of elements in both the sets is given to us in the form of variables mm and nn. We are also given that the number of subsets of set AA is greater than the number of subsets of set BB by a specific number. So, we will first calculate the difference in the total number of subsets for the two sets and then find the value of mm and nn.

Complete step by step answer:
So, the total number of elements in set AA is mm. Total number of elements in set BB is nn. Now, we know that the total number of subsets of a given set which consists of pp elements in total is 2p{2^p}. So, the total number of subsets of set AA is 2m{2^m}. Also, the total number of subsets of set BB is 2n{2^n}.

Now, we are given that the total number of subsets of AA is 112112 more than the total number of subsets of BB. So, nn must be less than m as the number of subsets of set BB is less than the number of subsets of set AA.
So, we get, 2m2n=112{2^m} - {2^n} = 112.
Now, taking 2n{2^n} common from left side of the equation, we get,
2n(2m2n1)=112\Rightarrow {2^n}\left( {\dfrac{{{2^m}}}{{{2^n}}} - 1} \right) = 112
Now, we factorize 112112 in the right side of the equation. Also, using the exponent law axay=axy\dfrac{{{a^x}}}{{{a^y}}} = {a^{x - y}} in the equation, we get,
2n(2(mn)1)=24×7\Rightarrow {2^n}\left( {{2^{\left( {m - n} \right)}} - 1} \right) = {2^4} \times 7
Now, we know that any power of two can only be equal to a power of two as it consists only of 22 as its factor. So, we equate 2n{2^n} with 24{2^4}. Hence, we will have to equate the factor (2(mn)1)\left( {{2^{\left( {m - n} \right)}} - 1} \right) with 77 so that the equation holds true. So, we get,
2n=24\Rightarrow {2^n} = {2^4} and (2(mn)1)=7\left( {{2^{\left( {m - n} \right)}} - 1} \right) = 7

So, adding one to both sides of (2(mn)1)=7\left( {{2^{\left( {m - n} \right)}} - 1} \right) = 7, we get both the equation as,
2n=24\Rightarrow {2^n} = {2^4} and 2(mn)=7+1=8{2^{\left( {m - n} \right)}} = 7 + 1 = 8
Now, we know that 88 can be expressed as 23{2^3}.
2n=24\Rightarrow {2^n} = {2^4} and 2(mn)=23{2^{\left( {m - n} \right)}} = {2^3}
Now, we compare the powers of two on both sides of the two equations. So, we get,
n=4\Rightarrow n = 4 and mn=3m - n = 3
So, we get the value of n as 44.
Now, we have to find the value of m. So, we put the value of n in the equation mn=3m - n = 3. So, we get,
m4=3\Rightarrow m - 4 = 3
Adding 44 to both sides of the equation, we get,
m=3+4\Rightarrow m = 3 + 4
m=7\therefore m = 7
Hence, we get the value of mm as 77.

Therefore, option A is the correct answer.

Note: We must know the formula for the total number of subsets of a given set in order to solve the given problem. One should know the simplification rules and algebraic rules like transposition to solve the equation that is formed while solving the problem. One must have a good knowledge of laws of exponents so as to get through with such types of problems.