Question

Two Faraday of electricity is passed through a solution of $CuSO_4$. The mass of copper deposited at the cathode is (At. mass of $Cu\, = \,63.5\, u$)

• A. $0\, g$
• B. $63.5\, g$
• C. $2\, g$
• D. $127\, g$

Answer 1

Answer: (B)

$63.5\, g$

Answer 2

$Cu ^{2+}+ Ze \rightarrow Cu$

2 mole deposit 1 mole of $Cu$
$2 F \Rightarrow 2$ mole $\rightarrow 1$ mole of $Cu$
$\Rightarrow 63.5\, gm$.