Two fair dice are thrown. The probability that the number of... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

Two fair dice are thrown. The probability that the number of times the first dice exceeds 3 and that the second exceeds 4 will be:

A

$\frac{2}{6}$

B

$\frac{5}{6}$

C

$\frac{1}{6}$

D

$\frac{3}{6}$

Answer

$\frac{1}{6}$

Explanation

Solution

The correct answer is (C): $\frac{1}{6}$