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Question

Mathematics Question on Venn Diagrams

Two events AA and BB will be independent if

A

A and B are mutually exclusive

B

P(AB)=(1P(A))(1P(B))P(A' \cap B') = (1 - P (A)) (1-P(B))

C

P(A)=P(B)P (A) = P(B)

D

P(A)+P(B)=1P (A) + P(B) = 1

Answer

P(AB)=(1P(A))(1P(B))P(A' \cap B') = (1 - P (A)) (1-P(B))

Explanation

Solution

If AA and BB are two independent events, then P(AB)=P(A)P(B)P(A \cap B)=P(A) \cdot P(B) Also, if AA and BB are independent then A' and B' are also independent. P(AB)=P(A)P(B) \therefore P\left(A' \cap B'\right) =P\left(A'\right) \cdot P\left(B'\right) =(1P(A))(1P(B))=(1-P(A))(1-P(B)) Again, if AA and BB are mutually exclusive, then P(AB)=0P(A \cap B)=0