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Question

Physics Question on Gravitation

Two equal masses separated by a distance d attract each other with a force (F). If one unit of mass is transferred from one of them to the Other, the force

A

does not change

B

decreases by (G/d2)(G/d^2)

C

becomes d2d^2 times

D

increases by (2G/d2)(2G/d^2)

Answer

decreases by (G/d2)(G/d^2)

Explanation

Solution

F(initial) = G.m.m d2 F(final )= G. (m+1)(m1)d2=G(m21)d2 F _{(\text {initial) }}=\frac{\text { G.m.m }}{ d ^{2}} \\\ F _{(\text {final })}=\frac{\text { G. }( m +1) \cdot( m -1)}{ d ^{2}}=\frac{ G \cdot\left( m ^{2}-1\right)}{ d ^{2}}
Clearly from above expressions we have a decrease in force by Gd2\frac{ G }{ d ^{2}}.