Solveeit Logo

Question

Question: Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulle...

Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled out symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass is

A

12kx2\frac { 1 } { 2 } k x ^ { 2 }

B

12kx2- \frac { 1 } { 2 } k x ^ { 2 }

C

14kx2\frac { 1 } { 4 } k x ^ { 2 }

D

14kx2- \frac { 1 } { 4 } k x ^ { 2 }

Answer

14kx2- \frac { 1 } { 4 } k x ^ { 2 }

Explanation

Solution

If the spring is stretched by length x, then work done by two equal masses = 12kx2\frac { 1 } { 2 } k x ^ { 2 }

So work done by each mass on the spring = 14kx2\frac { 1 } { 4 } k x ^ { 2 }

∴ Work done by spring on each mass = 14kx2- \frac { 1 } { 4 } k x ^ { 2 }.