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Question: Two equal charges \(q\) are placed at a distance of \(2a\) and a third charge \(- 2q\) is placed at ...

Two equal charges qq are placed at a distance of 2a2a and a third charge 2q- 2q is placed at the midpoint. The potential energy of the system is

A

q28πε0a\frac{q^{2}}{8\pi\varepsilon_{0}a}

B

6q28πε0a\frac{6q^{2}}{8\pi\varepsilon_{0}a}

C

7q28πε0a- \frac{7q^{2}}{8\pi\varepsilon_{0}a}

D

9q28πε0a\frac{9q^{2}}{8\pi\varepsilon_{0}a}

Answer

7q28πε0a- \frac{7q^{2}}{8\pi\varepsilon_{0}a}

Explanation

Solution

Usystem(fudk;)=14πε0(q)(2q)a+14πε0(2q)(q)a+14πε0(q)(q)2aU_{system(fudk;)} = \frac{1}{4\pi\varepsilon_{0}}\frac{(q)( - 2q)}{a} + \frac{1}{4\pi\varepsilon_{0}}\frac{( - 2q)(q)}{a} + \frac{1}{4\pi\varepsilon_{0}}\frac{(q)(q)}{2a}

Usystem(fudk;)=7q28πε0aU_{system(fudk;)} = - \frac{7q^{2}}{8\pi\varepsilon_{0}a}