Question

Two equal and opposite charges are placed at a certain distance, the force between them is F. If 25% of one charge is transferred to other, then the force between them is-

• A. F
• B. 9F/16
• C. 15F/16
• D. 4F/5

Answer 1

Answer: (B)

9F/16

Answer 2

$+ q \quad - q \quad + q - \frac { q } { 4 } \quad - q + \frac { q } { 4 }$

F = $\frac { \mathrm { kq } ^ { 2 } } { \mathrm { r } ^ { 2 } }$ F' =

= $\frac { 9 } { 16 }$ F