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Question: Two electric dipoles of moment P and 64 P are placed in opposite direction on a line at a distance o...

Two electric dipoles of moment P and 64 P are placed in opposite direction on a line at a distance of 25 cm. The electric field will be zero at point between the dipoles whose distance from the dipole of moment P is

A

5 cm

B

259\frac{25}{9}cm

C

10 cm

D

413\frac{4}{13} cm

Answer

5 cm

Explanation

Solution

Suppose neutral point N lies at a distance x from dipole of moment p or at a distance x2 from dipole of 64 p.

At N |E. F. due to dipole ①|= |E. F. due to dipole ②|

14πε0.2px3=14πε0.2(64p)(25x)3\frac{1}{4\pi\varepsilon_{0}}.\frac{2p}{x^{3}} = \frac{1}{4\pi\varepsilon_{0}}.\frac{2(64p)}{(25 - x)^{3}}

1x3=64(25x)3\frac{1}{x^{3}} = \frac{64}{(25 - x)^{3}} ⇒ x = 5 cm.