Question
Physics Question on electrostatic potential and capacitance
Two electric charge 12 μC and -6 μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero, The distance of P from -6 μC charge is
A
0.10 m
B
0.15 m
C
0.20 m
D
0.25 m
Answer
0.20 m
Explanation
Solution
Let P be at distance x from −6μC charge.
We know, potential V=rkq
Given, potential at P:VP=0
⇒(0.2+x)k×12×10−6+xk×(−6)×10−6=0
or, 0.2+x12=x6
or, 2x=0.2+x
or, x=0.2m