Question
Question: Two electric bulbs whose resistances are in the ratio of 1:2 are connected in series. The powers dis...
Two electric bulbs whose resistances are in the ratio of 1:2 are connected in series. The powers dissipated in them have the ratio
A
1 : 2
B
2 : 1
C
1 : 1
D
1 : 4
Answer
1 : 2
Explanation
Solution
In series, current is same in both the bulbs, hence P∝R(P=i2R) ∴P2P1=R2R1=21