Solveeit Logo

Question

Physics Question on Moment Of Inertia

Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities ω1 and ω2. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is

A

12l(ω1+ω2)2\frac 12l(ω_1+ω_2)^2

B

14l(ω1ω2)2\frac 14l(ω_1-ω_2)^2

C

l(ω1ω2)2l(ω_1-ω_2)^2

D

18(ω1ω2)2\frac 18(ω_1-ω_2)^2

Answer

14l(ω1ω2)2\frac 14l(ω_1-ω_2)^2

Explanation

Solution

The correct option is (B): 14l(ω1ω2)2\frac 14l(ω_1-ω_2)^2.