Question

Two dice are tossed together. The odds in favour of the sum of the numbers on them as 2 are

• A. 1 : 36
• B. 1 : 35
• C. 35 : 1
• D. None of these

Answer 1

Answer: (B)

1 : 35

Answer 2

If two dice are tossed, total number of events = 6 × 6

= 36.

Favourable event is (1, 1). Number of favourable events = 1

∴ odds in favour $= \frac { 1 } { 36 - 1 } = \frac { 1 } { 35 }$.