Question

Two dice are thrown together. The probability that sum of the two numbers will be a multiple of 4 is

• A. $\frac { 1 } { 9 }$
• B. $\frac { 1 } { 3 }$
• C. $\frac { 1 } { 4 }$
• D. $\frac { 5 } { 9 }$

Answer 1

Answer: (C)

$\frac { 1 } { 4 }$

Answer 2

$S = \{ ( 3,1 ) , ( 2,2 ) , ( 1,3 ) , ( 6,2 ) , ( 5,3 ) , ( 4,4 ) , ( 3,5 ) , ( 2,6 ) , ( 6,6 ) \}$

Hence required probability