Question

Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is 6

• A. $\frac { 5 } { 36 }$
• B. $\frac { 1 } { 6 }$
• C. $\frac { 2 } { 15 }$
• D. None of these

Answer 1

Answer: (C)

$\frac { 2 } { 15 }$

Answer 2

Obviously numbers will be$\left( \begin{array} { l l } \mathrm { I } & \mathrm { II } \\ 5 , & 1 \\ 4 , & 2 \\ 2 , & 4 \\ 1 , & 5 \end{array} \right)$

Hence required probability .