Question
Mathematics Question on Probability
Two dice are thrown independently Let A be the event that the number appeared on the 1st die is less than the number appeared on the 2nd die, B be the event that the number appeared on the 1st die is even and that on the second die is odd, and C be the event that the number appeared on the 1st die is odd and that on the 2nd is even Then :
A and B are mutually exclusive
the number of favourable cases of the events A,B and C are 15, 6 and 6 respectively
B and C are independent
the number of favourable cases of the event (A∪B)∩C is 6
the number of favourable cases of the event (A∪B)∩C is 6
Solution
A : no. on 1st die < no. on 2nd die
A : no. on 1st die = even & no. of 2nd die = odd
C: no. on 1st die = odd & no. on 2nd die = even
n(A)=5+4+3+2+1=15
n(B)=9
n(C)=9
n((A∪B)∩C)=(A∩C)∪(B∩C)
=(3+2+1)+0=6