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Question

Mathematics Question on Probability

Two dice are thrown independently Let AA be the event that the number appeared on the 1st 1^{\text {st }} die is less than the number appeared on the 2nd 2^{\text {nd }} die, BB be the event that the number appeared on the 1st 1^{\text {st }} die is even and that on the second die is odd, and CC be the event that the number appeared on the 1st 1^{\text {st }} die is odd and that on the 2nd 2^{\text {nd }} is even Then :

A

A and B are mutually exclusive

B

the number of favourable cases of the events A,BA , B and CC are 15, 6 and 6 respectively

C

BB and CC are independent

D

the number of favourable cases of the event (AB)C( A \cup B ) \cap C is 6

Answer

the number of favourable cases of the event (AB)C( A \cup B ) \cap C is 6

Explanation

Solution

A : no. on 1st die < no. on 2nd die
A : no. on 1st die = even & no. of 2nd die = odd
C: no. on 1st die = odd & no. on 2nd die = even
n(A)=5+4+3+2+1=15
n(B)=9
n(C)=9
n((A∪B)∩C)=(A∩C)∪(B∩C)
=(3+2+1)+0=6