Question

Two dice are thrown. If first shows 5, then the probability that the sum of the numbers appears on both is 8 or more than 8, is

• A. $\frac { 1 } { 12 }$
• B. $\frac { 11 } { 12 }$
• C. $\frac { 1 } { 3 }$
• D. $\frac { 2 } { 3 }$

Answer 1

Answer: (D)

$\frac { 2 } { 3 }$

Answer 2

Required probability $= \frac { 4 } { 6 } = \frac { 2 } { 3 }$.