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Question: Two cylinders A and B fitted with the pistons contain an equal amount of an ideal diatomic gas at \(...

Two cylinders A and B fitted with the pistons contain an equal amount of an ideal diatomic gas at 300K300K . Piston A is free to move and piston B is fixed. The same amount of heat is given to the gases in two cylinders. Temperature of the gas in cylinder A increases by 30K30K . Then, increase in temperature of the gas in cylinder B is:
( γ=1.4\gamma = 1.4 for diatomic gas)
(A) 36K36K
(B) 54K54K
(C) 42K42K
(D) 24K24K

Explanation

Solution

Given that the two cylinders A and B are fitted with pistons. Also they have diatomic gas. Piston A is free to move which means pressure remains constant and piston B is fixed which means that the volume inside that cylinder remains constant. So using the ratio of the specific heat we can find the increase in temperature.

Complete answer:
Piston A is free to move. That means that the pressure inside that cylinder will be constant, which means the process is isobaric.
Thus for given heat to the system is
ΔQA=nCpΔTA(1)\therefore \Delta {Q_A} = n{C_p}\Delta {T_A} \ldots \ldots \left( 1 \right)
Piston B is fixed. This implies that the volume inside the cylinder is constant. This means that the process is isochoric.
Thus for the given heat to the system is
ΔQB=nCvΔTB(2)\therefore \Delta {Q_B} = n{C_v}\Delta {T_B} \ldots \ldots \left( 2 \right)
Given in the question is that the same heat is given to both the cylinders. Therefore,
ΔQA=ΔQB\Delta {Q_A} = \Delta {Q_B} ……..(3)
Therefore equating (1) and (2)
nCpΔTA=nCvΔTBn{C_p}\Delta {T_A} = n{C_v}\Delta {T_B} ……… (4)
ΔTB=(CpCv)ΔTA\Delta {T_B} = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right)\Delta {T_A} ………. (5)
The ratio of the specific heat is given as,
γ=(CpCv)=1.4\gamma = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right) = 1.4 for diatomic gases.
Also, the increase in temperature for cylinder A is given as
ΔTA=30K\Delta {T_A} = 30K
Substituting both the values in the equation (5),
ΔTB=1.4×30K\Delta {T_B} = 1.4 \times 30K
ΔTB=42K\Delta {T_B} = 42K
Therefore the correct option is C.

Note:
Note that the specific heat capacity of a body is the amount of heat required to raise the temperature of the body of unit mass from 00C{0^0}C to 10C{1^0}C . It is represented by C and its units are usually calories or Joule/KgKJoule/KgK . The specific heat capacity of water at room temperature is higher than most other materials. We use this property of water in our body to maintain constant body temperature.