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Question

Chemistry Question on Gas laws

Two cylinders A and B fitted with pistons contain equal amounts of an ideal diatomic gas at 300 K. The piston of A is free to move, while that of B is held fixed. The same amount of heat is given to the gas in each cylinder. If the rise in temperature of the gas in A is 30 K, then the rise in temperature of the gas in B is

A

30 K

B

18 K

C

50 K

D

42 K

Answer

42 K

Explanation

Solution

A is free to move, therefore, heat will be supplied at constant
pressure
dQA=nCpdtA\therefore \, \, \, \, \, \, \, dQ_A=nC_p dt_A \, \, \, \, \, \, \, \, \, \, \, \, ...(i)
B is held fixed, therefore, heat will be supplied at constant
volume.
dQB=nCvdTB\therefore \, \, \, \, \, \, \, \, \, \, \, \, \, dQ_B=nC_vdT_B \, \, \, \, \, \, \, \, \, \, \, \, ...(ii)
But dQA=dQB\, \, \, \, \, \, \, \, \, \, \, \, dQ_A =dQ_B \, \, \, \, \, \, \, \, \, \, \, \, \, \, (given)
nCpdtA=nCvdTB\therefore \, \, \, \, \, \, \, \, \, \, \, \, \, _nC_pdt_A=nCvdT_B
dTB=(CpCv)dTA\therefore \, \, \, \, \, \, \, \, \, \, dT_B=\big(\frac{C_p}{C_v}\bigg)dT_A
=λ(dTA)[γ=1.4(diatomic)]\, \, \, \, \, \, \, \, \, \, \, \, \, \, =\lambda(dT_A) \, \, \, \, \, [\gamma =1.4 (diatomic)]
(dTA=30K)\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, (dT_A=30 K)
=(1.4)(30K)\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =(1.4)(30 K)
dTB=42K\therefore \, \, \, \, \, \, \, \, \, \, dT_B=42 K