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Question

Physics Question on Relative Velocity

Two curs 1 & 2 starting from rest are moving With speeds V1V_1 and V2m/s(V1>V2)V_2 \,m/s (V_1 > V_2) Car 2 is ahead of car '1' by s meter when the driver of the car 1 sees car '2'. What minimum retardation should be given to car '1' to avoid collision

A

V1V2S\frac{V_1 - V_2}{S}

B

V1+V2S\frac{V_1 + V_2}{S}

C

(V1+V2)22S\frac{(V_1 + V_2)^2}{2S}

D

(V1V2)22S\frac{(V_1 - V_2)^2}{2S}

Answer

(V1V2)22S\frac{(V_1 - V_2)^2}{2S}

Explanation

Solution

Relative velocity = (ν1ν2)=ν( \nu_1 - \nu_2) = \nu and ν2u2=2as(u=0)\nu^2 - u^2 = 2as (u = 0)