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Question: Two containers of equal volume contain the same gas at pressures \(P_{1}\) and \(P_{2}\)and absolute...

Two containers of equal volume contain the same gas at pressures P1P_{1} and P2P_{2}and absolute temperatures T1T_{1} and T2T_{2} respectively. On joining the vessels, the gas reaches a common pressure P and common temperature T. The ratio P/T is equal to

A

P1T1+P2T2\frac{P_{1}}{T_{1}} + \frac{P_{2}}{T_{2}}

B

P1T1+P2T2(T1+T2)2\frac{P_{1}T_{1} + P_{2}T_{2}}{(T_{1} + T_{2})^{2}}

C

P1T2+P2T1(T1+T2)2\frac{P_{1}T_{2} + P_{2}T_{1}}{(T_{1} + T_{2})^{2}}

D

P12T1+P22T2\frac{P_{1}}{2T_{1}} + \frac{P_{2}}{2T_{2}}

Answer

P12T1+P22T2\frac{P_{1}}{2T_{1}} + \frac{P_{2}}{2T_{2}}

Explanation

Solution

Number of moles in first vessel μ1=P1VRT1\mu_{1} = \frac{P_{1}V}{RT_{1}} and number of

moles in second vessel μ2=P2VRT2\mu_{2} = \frac{P_{2}V}{RT_{2}}

If both vessels are joined together then quantity of gas

remains same i.e μ=μ1+μ2\mu = \mu_{1} + \mu_{2}

P(2V)RT=P1VRT1+P2VRT2\frac{P(2V)}{RT} = \frac{P_{1}V}{RT_{1}} + \frac{P_{2}V}{RT_{2}}

PT=P12T1+P22T2\frac{P}{T} = \frac{P_{1}}{2T_{1}} + \frac{P_{2}}{2T_{2}}