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Question: Two containers A & B contain ideal gases helium and oxygen respectively. Volume of both containers a...

Two containers A & B contain ideal gases helium and oxygen respectively. Volume of both containers are equal and pressure is also equal. Container A has twice the number of molecules than container B then if vA&vB represent the rms speed of gases in containers A & B respectively, then -

A

A

vAvB\frac{v_{A}}{v_{B}} = 2\sqrt{2}

B

vAvB\frac{v_{A}}{v_{B}}= 4

C

vAvB\frac{v_{A}}{v_{B}} = 2

D

vAvB\frac{v_{A}}{v_{B}} = 8\sqrt{8}

Answer

vAvB\frac{v_{A}}{v_{B}} = 2

Explanation

Solution

TA = PAVAnAR\frac{P_{A}V_{A}}{n_{A}R} and TB = PBVBnBR\frac{P_{B}V_{B}}{n_{B}R}

Given, PA = PB , VA = VB and nA = 2nB

\ TA = TB2\frac{T_{B}}{2}

Now, VAVB=TATB×MBMA\frac{V_{A}}{V_{B}} = \sqrt{\frac{T_{A}}{T_{B}} \times \frac{M_{B}}{M_{A}}} = 2