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Question: Two containers A & B contain ideal gases helium and oxygen respectively. Volume of both containers a...

Two containers A & B contain ideal gases helium and oxygen respectively. Volume of both containers are equal and pressure is also equal. Container A has twice the number of molecules than container B then if vA&vB represent the rms speed of gases in containers A & B respectively, then**–**

A

A

vAvB\frac{v_{A}}{v_{B}} = 2\sqrt{2}

B

vAvB\frac{v_{A}}{v_{B}}= 4

C

vAvB\frac{v_{A}}{v_{B}} = 2

D

vAvB\frac{v_{A}}{v_{B}} = 8\sqrt{8}

Answer

vAvB\frac{v_{A}}{v_{B}} = 2

Explanation

Solution

PV = nRT Ž TA = TB2\frac{T_{B}}{2}

vrms µTM\sqrt{\frac{T}{M}}

Ž vAvB\frac{v_{A}}{v_{B}} = TATB×MBMA\sqrt{\frac{T_{A}}{T_{B}} \times \frac{M_{B}}{M_{A}}} = 12×16×24\sqrt{\frac{1}{2} \times \frac{16 \times 2}{4}}

vAvB\frac{v_{A}}{v_{B}} = 2