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Question: Two consecutive sides of a parallelogram are \(4 x + 5 y = 0\) and \(7 x + 2 y = 0\) If the equati...

Two consecutive sides of a parallelogram are 4x+5y=04 x + 5 y = 0 and 7x+2y=07 x + 2 y = 0 If the equation to one diagonal is 11x+7y=911 x + 7 y = 9 then the equation of the other diagonal is.

A

x+2y=0x + 2 y = 0

B

2x+y=02 x + y = 0

C

xy=0x - y = 0

D

None of these

Answer

xy=0x - y = 0

Explanation

Solution

Since equation of diagonal 11x+7y=911 x + 7 y = 9 does not pass through origin, so it cannot be the equation of the diagonal OB. Thus on solving the equation AC with the equations OA and OC, we get A(53,43)A \left( \frac { 5 } { 3 } , - \frac { 4 } { 3 } \right) and C(23,73)C \left( \frac { - 2 } { 3 } , \frac { 7 } { 3 } \right).

Therefore, the middle point M is (12,12)\left( \frac { 1 } { 2 } , \frac { 1 } { 2 } \right)

Hence the equation of OB is y=xy = x i.e.,xy=0x - y = 0.