Question

Two conducting spheres each of radius R carry charge q. They are placed at a distance r from each other where r > 2R. The neutral point lies at a distance r/2 from either sphere. If the electric field at the neutral point due to either sphere be E then the total electric potential at that point will be –

• A. $\frac{rE}{2}$
• B. rE
• C. $\frac{RE}{2}$
• D. RE

Answer 1

Answer: (B)

rE

Answer 2

E_P (each sphere) = $\frac { \mathrm { kq } } { \left( \frac { \mathrm { r } } { 2 } \right) ^ { 2 } }$ = $\frac { 4 \mathrm { kq } } { \mathrm { r } ^ { 2 } }$

E = $\frac { 4 \mathrm { kq } } { \mathrm { r } ^ { 2 } }$ Ž q =

V_P = = $\frac { 4 \mathrm { Er } ^ { 2 } } { \mathrm { r } \times 4 }$ = Er