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Question

Physics Question on Electromagnetic induction

Two conducting circular loops A and B are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them is:
Circle

A

μ0πa22b\frac{\mu_0 \pi a^2}{2b}

B

μ02πb2a\frac{\mu_0}{2\pi} \cdot \frac{b^2}{a}

C

μ0πb22a\frac{\mu_0 \pi b^2}{2a}

D

μ02πa2b\frac{\mu_0}{2\pi} \cdot \frac{a^2}{b}

Answer

μ0πa22b\frac{\mu_0 \pi a^2}{2b}

Explanation

Solution

The magnetic flux (ϕ\phi) through loop B due to current in loop A is given by:

ϕ=Mi=BA\phi = M \cdot i = B \cdot A

The mutual inductance is:

M=μ0πa22bM = \frac{\mu_0 \pi a^2}{2b}

where aa is the radius of loop A, bb is the distance between the loops, and μ0\mu_0 is the permeability of free space.