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Question: Two condensers, one of capacity C and other of capacity \(\frac{C}{2}\)are connected to a V volt bat...

Two condensers, one of capacity C and other of capacity C2\frac{C}{2}are connected to a V volt battery. As shown in the figure. The work done in charging fully both the condensers is

A

14CV2\frac{1}{4}CV^{2}

B

34CV2\frac{3}{4}CV^{2}

C

12CV2\frac{1}{2}CV^{2}

D

2CV22CV^{2}

Answer

34CV2\frac{3}{4}CV^{2}

Explanation

Solution

:

As the capacitors are connected in parallel, therefore potential difference across both the condensers remains the same.

q1=CV,q2=C2V\therefore q_{1} = CV,q_{2} = \frac{C}{2}V

Also q=q1+q2=CV+C2V=32CVq = q_{1} + q_{2} = CV + \frac{C}{2}V = \frac{3}{2}CV

Work done in charging fully both the condensers is given by

W=12qV=12×(32CV)V=34CV2W = \frac{1}{2}qV = \frac{1}{2} \times \left( \frac{3}{2}CV \right)V = \frac{3}{4}CV^{2}