Question

Two condensers C₁ and C₂ in a circuit are joined as shown in figure. The potential of point A is V₁ and that of B is V₂. The potential of point D will be

• A. $\frac{1}{2}$ (V₁ + V₂)
• B. $\frac{C_{2}V_{1} + C_{1}V_{2}}{C_{1} + C_{2}}$
• C. $\frac{C_{1}V_{1} + C_{2}V_{2}}{C_{1} + C_{2}}$
• D. $\frac{C_{2}V_{1} - C_{1}V_{2}}{C_{1} + C_{2}}$

Answer 1

Answer: (C)

$\frac{C_{1}V_{1} + C_{2}V_{2}}{C_{1} + C_{2}}$

Answer 2

C₁(V₁ – V_D) = C₂ (V_D – V₂)

C₁V₁ – C₁V_D = C₂V_D – C₂V₂