Question

Two concentric thin metallic spheres of radii R₁ and R₂ (R₁> R₂) bear charges Q₁ and Q₂ respectively. Then the potential at radius r between R₁ and R₂ will be 1/(4pe₀) times –

• A. $\frac{Q_{1} + Q_{2}}{r}$
• B. $\frac{Q_{1}}{R_{1}}$+$\frac{Q_{2}}{r}$
• C. $\frac{Q_{1}}{R_{1}}$+$\frac{Q_{2}}{R_{2}}$
• D. $\frac{Q_{1}}{R_{2}}$+$\frac{Q_{2}}{R_{1}}$

Answer 1

Answer: (B)

$\frac{Q_{1}}{R_{1}}$+$\frac{Q_{2}}{r}$

Answer 2

V = $\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$ $\frac { \mathrm { Q } _ { 2 } } { \mathrm { r } }$ + $\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$

= $\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$ $\left( \frac { \mathrm { Q } _ { 2 } } { \mathrm { r } } + \frac { \mathrm { Q } _ { 1 } } { \mathrm { R } _ { 1 } } \right)$