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Question: Two coils of self-inductance 2 mH and 8 mH are placed so close together that the effective flux in o...

Two coils of self-inductance 2 mH and 8 mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils are

A

16 mH

B

10 mH

C

6 mH

D

4 mH

Answer

4 mH

Explanation

Solution

Mutual inductance between coils is

M=kL1+L2M = k\sqrt{L_{1} + L_{2}}

=12×103×8×103= 1\sqrt{2 \times 10^{- 3} \times 8 \times 10^{- 3}} (k=1\because k = 1)

=4×103H=4mH= 4 \times 10^{- 3}H = 4mH