Question
Physics Question on Youngs double slit experiment
Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are
A
5I and I
B
5I and 3 I
C
9I and I
D
9I and 3 I
Answer
9I and I
Explanation
Solution
Imax=(I1+I2)2=(4I+I)2=9I Imin=(I1−I2)2=(4I−I)2=I ∴ Correct option is (c ).