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Question

Physics Question on wave interference

Two coherent monochromatic light beams of intensities II and 9 II are superimposed. The maximum and the minimum intensities of the resultant beams are

A

10 II and zero

B

10 II and 8 II

C

10 II and 4 II

D

16 II and 4 II

Answer

16 II and 4 II

Explanation

Solution

The ratio of maximum to minimum intensities is ImaxImin=(I1+I2)2(I1I2)2\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}}{{{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}} =(1+3)2(13)2=4222=\frac{{{(1+3)}^{2}}}{{{(1-3)}^{2}}}=\frac{{{4}^{2}}}{{{2}^{2}}} =164=\frac{16}{4}