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Question: Two coherent light sources S<sub>1</sub> and S<sub>2</sub> (λ= 6000 Å) are 1mm apart from each other...

Two coherent light sources S1 and S2 (λ= 6000 Å) are 1mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be.

A

0.015 cm

B

0.025 cm

C

0.010 cm

D

0.030 cm

Answer

0.015 cm

Explanation

Solution

β=6000×10−10×25×10−210−3\beta = \frac{6000 \times 10^{- 10} \times 25 \times 10^{- 2}}{10^{- 3}}

∴λglass<λair 6mu 6mu(∵ 6muCglass<Cair)\therefore\lambda_{glass} < \lambda_{air}\mspace{6mu}\mspace{6mu}(\because\mspace{6mu} C_{glass} < C_{air}).